Let’s say you want iterate over a series of sequential numbers with Bash. If so, then you could do the following:
$ for i in {1..10}; do echo $i; done
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Now, let’s say you want to loop over a sequence of numbers, but you want to skip over by 10 each time:
$ for i in `seq 0 10 100`; do echo $i; done
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Supposedly, this syntax should work, but it is not on a Mac at least: for i in {0..100..10}; do echo $i; done
(see source). It does work on an Amazon Linux instance though:
$ for i in {0..100..10}; do echo $i; done
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$ cat /etc/os-release
NAME="Amazon Linux AMI"
VERSION="2018.03"
ID="amzn"
ID_LIKE="rhel fedora"
VERSION_ID="2018.03"
PRETTY_NAME="Amazon Linux AMI 2018.03"
ANSI_COLOR="0;33"
CPE_NAME="cpe:/o:amazon:linux:2018.03:ga"
HOME_URL="http://aws.amazon.com/amazon-linux-ami/"
Now, let’s say you want to skip over gaps that are not as well distributed or evenly spaced. This is probably not the most elegant solution; however, it works:
$ for i in `seq 3 5` `seq 7 10`; do echo $i; done
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